What are the solutions to the equation 3x^2+7=0 ?

The solutions to the equation 3x^2+7=0 are x=sqrt(7/3)i,x=-sqrt(7/3)i

Find the zeros of 3x^2+7=0

The zeros of 3x^2+7=0 are x=sqrt(7/3)i,x=-sqrt(7/3)i

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3 x^{2} + 7 = 0

x = \frac{7}{3} i, x = - \frac{7}{3} i

Solution steps

3 x^{2} + 7 = 0

Move

7

to the right side

3 x^{2} = - 7

Divide both sides by

3

x^{2} = - \frac{7}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{7}{3}, x = - - \frac{7}{3}

- \frac{7}{3} = \frac{7}{3} i

- - \frac{7}{3} = - \frac{7}{3} i

x = \frac{7}{3} i, x = - \frac{7}{3} i

3 (8)^{\frac{1}{3}}

\frac{10}{- 5}

\frac{80}{5}

\frac{π}{2} - \frac{π}{6}

(4) = (\frac{4}{5}) (- 2) - 4

What are the solutions to the equation 3x^2+7=0 ?
The solutions to the equation 3x^2+7=0 are x=sqrt(7/3)i,x=-sqrt(7/3)i
Find the zeros of 3x^2+7=0
The zeros of 3x^2+7=0 are x=sqrt(7/3)i,x=-sqrt(7/3)i