What are the solutions to the equation 4=2x^2-4 ?

The solutions to the equation 4=2x^2-4 are x=2,x=-2

Find the zeros of 4=2x^2-4

The zeros of 4=2x^2-4 are x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 = 2 x^{2} - 4

x = 2, x = - 2

Solution steps

4 = 2 x^{2} - 4

Switch sides

2 x^{2} - 4 = 4

Move

4

to the right side

2 x^{2} = 8

Divide both sides by

2

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

(2 y + 20)^{2} = 27

- x^{2} + 6 x + 1

x^{2} - 144 x = 0

3 x^{2} + 12 x + 28 = 0

(x + 2) (2 x - 5) = 0

What are the solutions to the equation 4=2x^2-4 ?
The solutions to the equation 4=2x^2-4 are x=2,x=-2
Find the zeros of 4=2x^2-4
The zeros of 4=2x^2-4 are x=2,x=-2