What are the solutions to the equation 7+5x-2x^2=0 ?

The solutions to the equation 7+5x-2x^2=0 are x=-1,x= 7/2

Find the zeros of 7+5x-2x^2=0

The zeros of 7+5x-2x^2=0 are x=-1,x= 7/2

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7 + 5 x - 2 x^{2} = 0

x = - 1, x = \frac{7}{2}

Decimal Notation

x = - 1, x = 3.5

Solution steps

7 + 5 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 7 = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 ( - 2 )}, x_{2} = \frac{- 5 - 9}{2 ( - 2 )}

x = \frac{- 5 + 9}{2 ( - 2 )} : - 1

x = \frac{- 5 - 9}{2 ( - 2 )} : \frac{7}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{7}{2}

11 a^{2} = - 4 a + 8

x^{2} + 110 = 18 x + 45

0 = 2 + 6 t - 4.9 t^{2}

8 x^{2} + 40 x + 50 = 0

x^{2} + 4 x + \frac{7}{4} = 0

What are the solutions to the equation 7+5x-2x^2=0 ?
The solutions to the equation 7+5x-2x^2=0 are x=-1,x= 7/2
Find the zeros of 7+5x-2x^2=0
The zeros of 7+5x-2x^2=0 are x=-1,x= 7/2