What are the solutions to the equation m^2+15m+50=0 ?

The solutions to the equation m^2+15m+50=0 are m=-5,m=-10

Find the zeros of m^2+15m+50=0

The zeros of m^2+15m+50=0 are m=-5,m=-10

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m^{2} + 15 m + 50 = 0

m = - 5, m = - 10

Solution steps

m^{2} + 15 m + 50 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 50 = 5

m_{1, 2} = \frac{- 15 \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 15 + 5}{2 \cdot 1}, m_{2} = \frac{- 15 - 5}{2 \cdot 1}

m = \frac{- 15 + 5}{2 \cdot 1} : - 5

m = \frac{- 15 - 5}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

m = - 5, m = - 10

9 t^{2} - 15 t - 14 = 0

x^{2} - 4 x - 21

4 x^{2} - 17 x + 1 = 0

x^{2} + 3 x = 0

2 x^{2} + 3 x + 14 = 0

What are the solutions to the equation m^2+15m+50=0 ?
The solutions to the equation m^2+15m+50=0 are m=-5,m=-10
Find the zeros of m^2+15m+50=0
The zeros of m^2+15m+50=0 are m=-5,m=-10