What are the solutions to the equation (x-3)^2=128 ?

The solutions to the equation (x-3)^2=128 are x=8sqrt(2)+3,x=-8sqrt(2)+3

Find the zeros of (x-3)^2=128

The zeros of (x-3)^2=128 are x=8sqrt(2)+3,x=-8sqrt(2)+3

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(x - 3)^{2} = 128

x = 82 + 3, x = - 82 + 3

Decimal Notation

x = 14.31370 \dots, x = - 8.31370 \dots

Solution steps

(x - 3)^{2} = 128

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 128 : x = 82 + 3

Solve

x - 3 = - 128 : x = - 82 + 3

The solutions to the quadratic equation are:

x = 82 + 3, x = - 82 + 3

x^{2} - \frac{4}{5} x = \frac{1}{5}

2 x^{2} + 6 = 10

x, x^{2} - 9 x + 3 = 3

3 u^{2} = 30 u - 9

g (8) = n^{2} + 3

What are the solutions to the equation (x-3)^2=128 ?
The solutions to the equation (x-3)^2=128 are x=8sqrt(2)+3,x=-8sqrt(2)+3
Find the zeros of (x-3)^2=128
The zeros of (x-3)^2=128 are x=8sqrt(2)+3,x=-8sqrt(2)+3