What are the solutions to the equation 2x^2=20-3x^2 ?

The solutions to the equation 2x^2=20-3x^2 are x=2,x=-2

Find the zeros of 2x^2=20-3x^2

The zeros of 2x^2=20-3x^2 are x=2,x=-2

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2 x^{2} = 20 - 3 x^{2}

x = 2, x = - 2

Solution steps

2 x^{2} = 20 - 3 x^{2}

Move

3 x^{2}

to the left side

5 x^{2} = 20

Divide both sides by

5

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x, x^{2} + 8 x - 2 = 0

x^{2} + 18 x + 63 = 0

3 (3 x + 2) - 6 x - 5 = 4 x^{2}

x^{2} - 116 = 0

x^{2} + 2 (4) x - 3 = (4) x^{2} + 1

What are the solutions to the equation 2x^2=20-3x^2 ?
The solutions to the equation 2x^2=20-3x^2 are x=2,x=-2
Find the zeros of 2x^2=20-3x^2
The zeros of 2x^2=20-3x^2 are x=2,x=-2