What are the solutions to the equation x^2+50x-150=0 ?

The solutions to the equation x^2+50x-150=0 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))

Find the zeros of x^2+50x-150=0

The zeros of x^2+50x-150=0 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))

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x^{2} + 50 x - 150 = 0

x = 5 (31 - 5), x = - 5 (5 + 31)

Decimal Notation

x = 2.83882 \dots, x = - 52.83882 \dots

Solution steps

x^{2} + 50 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 1 \cdot ( - 150 )}{2 \cdot 1}

5 0^{2} - 4 \cdot 1 \cdot (- 150) = 1031

x_{1, 2} = \frac{- 50 \pm 10 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 50 + 10 31}{2 \cdot 1}, x_{2} = \frac{- 50 - 10 31}{2 \cdot 1}

x = \frac{- 50 + 10 31}{2 \cdot 1} : 5 (31 - 5)

x = \frac{- 50 - 10 31}{2 \cdot 1} : - 5 (5 + 31)

The solutions to the quadratic equation are:

x = 5 (31 - 5), x = - 5 (5 + 31)

3 x^{2} - 3 x = 18

- x^{2} - 6 x = - 2 x

x^{2} - 2.5 x - 4 = 0

(3 x + 8) (3 - 2 x) = 0

x^{2} + 2 x + 1 = 6

What are the solutions to the equation x^2+50x-150=0 ?
The solutions to the equation x^2+50x-150=0 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))
Find the zeros of x^2+50x-150=0
The zeros of x^2+50x-150=0 are x=5(sqrt(31)-5),x=-5(5+sqrt(31))