What are the solutions to the equation 3x(x+2)-5(x-3)=17 ?

The solutions to the equation 3x(x+2)-5(x-3)=17 are x= 2/3 ,x=-1

Find the zeros of 3x(x+2)-5(x-3)=17

The zeros of 3x(x+2)-5(x-3)=17 are x= 2/3 ,x=-1

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3 x (x + 2) - 5 (x - 3) = 17

x = \frac{2}{3}, x = - 1

Decimal Notation

x = 0.66666 \dots, x = - 1

Solution steps

3 x (x + 2) - 5 (x - 3) = 17

Expand

3 x (x + 2) - 5 (x - 3) : 3 x^{2} + x + 15

3 x^{2} + x + 15 = 17

Move

17

to the left side

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

3 x^{2} - 22 x = 16

x^{2} + (3 + x)^{2} = (6 + x)^{2}

- 9 x^{2} + 2 = 0

(x - 6)^{2} = - 3

3 y^{2} - 4 y + 2 = 0

What are the solutions to the equation 3x(x+2)-5(x-3)=17 ?
The solutions to the equation 3x(x+2)-5(x-3)=17 are x= 2/3 ,x=-1
Find the zeros of 3x(x+2)-5(x-3)=17
The zeros of 3x(x+2)-5(x-3)=17 are x= 2/3 ,x=-1