What are the solutions to the equation (2x-4)^2=80 ?

The solutions to the equation (2x-4)^2=80 are x=2(1+sqrt(5)),x=2(1-sqrt(5))

Find the zeros of (2x-4)^2=80

The zeros of (2x-4)^2=80 are x=2(1+sqrt(5)),x=2(1-sqrt(5))

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(2 x - 4)^{2} = 80

x = 2 (1 + 5), x = 2 (1 - 5)

Decimal Notation

x = 6.47213 \dots, x = - 2.47213 \dots

Solution steps

(2 x - 4)^{2} = 80

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 80 : x = 2 (1 + 5)

Solve

2 x - 4 = - 80 : x = 2 (1 - 5)

The solutions to the quadratic equation are:

x = 2 (1 + 5), x = 2 (1 - 5)

C, C^{2} = a^{2} + b^{2}

x^{2} + 6 x - 80 = 0

x^{2} - 4 = 6 x

x^{2} - 4 = 10

(x - 6)^{2} = x + 24

What are the solutions to the equation (2x-4)^2=80 ?
The solutions to the equation (2x-4)^2=80 are x=2(1+sqrt(5)),x=2(1-sqrt(5))
Find the zeros of (2x-4)^2=80
The zeros of (2x-4)^2=80 are x=2(1+sqrt(5)),x=2(1-sqrt(5))