What are the solutions to the equation 2x^2-20x=22 ?

The solutions to the equation 2x^2-20x=22 are x=11,x=-1

Find the zeros of 2x^2-20x=22

The zeros of 2x^2-20x=22 are x=11,x=-1

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2 x^{2} - 20 x = 22

x = 11, x = - 1

Solution steps

2 x^{2} - 20 x = 22

Move

22

to the left side

2 x^{2} - 20 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 ( - 22 )}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 (- 22) = 24

x_{1, 2} = \frac{- ( - 20 ) \pm 24}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 24}{2 \cdot 2}, x_{2} = \frac{- ( - 20 ) - 24}{2 \cdot 2}

x = \frac{- ( - 20 ) + 24}{2 \cdot 2} : 11

x = \frac{- ( - 20 ) - 24}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 11, x = - 1

- 3 x^{2} + 2 x = - 3

x^{2} + 16 x - 64 = 0

x^{2} - 6 x - 34 = 0

2 p^{2} - 50 = 0

2 x^{2} + 8 x - 24 = 0

What are the solutions to the equation 2x^2-20x=22 ?
The solutions to the equation 2x^2-20x=22 are x=11,x=-1
Find the zeros of 2x^2-20x=22
The zeros of 2x^2-20x=22 are x=11,x=-1