What are the solutions to the equation 128-2b^2=0 ?

The solutions to the equation 128-2b^2=0 are b=8,b=-8

Find the zeros of 128-2b^2=0

The zeros of 128-2b^2=0 are b=8,b=-8

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128 - 2 b^{2} = 0

b = 8, b = - 8

Solution steps

128 - 2 b^{2} = 0

Move

128

to the right side

- 2 b^{2} = - 128

Divide both sides by

- 2

b^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 64, b = - 64

64 = 8

- 64 = - 8

b = 8, b = - 8

x^{2} - 1300 x + 360000 = 0

6 x^{2} + (2 n + 3) x + n = 0

p^{2} - 41 p + 400 = 0

x, (x - 5)^{2} = 9

- (x + 1)^{2} = - 81

What are the solutions to the equation 128-2b^2=0 ?
The solutions to the equation 128-2b^2=0 are b=8,b=-8
Find the zeros of 128-2b^2=0
The zeros of 128-2b^2=0 are b=8,b=-8