What are the solutions to the equation m^2+11m=-30 ?

The solutions to the equation m^2+11m=-30 are m=-5,m=-6

Find the zeros of m^2+11m=-30

The zeros of m^2+11m=-30 are m=-5,m=-6

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m^{2} + 11 m = - 30

m = - 5, m = - 6

Solution steps

m^{2} + 11 m = - 30

Move

30

to the left side

m^{2} + 11 m + 30 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 30 = 1

m_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 11 + 1}{2 \cdot 1}, m_{2} = \frac{- 11 - 1}{2 \cdot 1}

m = \frac{- 11 + 1}{2 \cdot 1} : - 5

m = \frac{- 11 - 1}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = - 5, m = - 6

x^{(2)} + 5 x + 6 = 0

x, f (a + h) = - 5 x^{2} + 2 x - 1

x, f (x)^{2} = x + 2

x^{1} - x^{2} = 4

- 2 x^{2} - 2 x + 5 = 0

What are the solutions to the equation m^2+11m=-30 ?
The solutions to the equation m^2+11m=-30 are m=-5,m=-6
Find the zeros of m^2+11m=-30
The zeros of m^2+11m=-30 are m=-5,m=-6