What are the solutions to the equation -16t^2-3t+70=0 ?

The solutions to the equation -16t^2-3t+70=0 are t=-35/16 ,t=2

Find the zeros of -16t^2-3t+70=0

The zeros of -16t^2-3t+70=0 are t=-35/16 ,t=2

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- 16 t^{2} - 3 t + 70 = 0

t = - \frac{35}{16}, t = 2

Decimal Notation

t = - 2.1875, t = 2

Solution steps

- 16 t^{2} - 3 t + 70 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 16 ) \cdot 70}{2 ( - 16 )}

(- 3)^{2} - 4 (- 16) \cdot 70 = 67

t_{1, 2} = \frac{- ( - 3 ) \pm 67}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 67}{2 ( - 16 )}, t_{2} = \frac{- ( - 3 ) - 67}{2 ( - 16 )}

t = \frac{- ( - 3 ) + 67}{2 ( - 16 )} : - \frac{35}{16}

t = \frac{- ( - 3 ) - 67}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

t = - \frac{35}{16}, t = 2

(x + 4)^{2} = 400

5 (x + 3)^{2} = 60

(x^{2} + 4) - (x - 2) (3 - 2 x) = 0

x^{2} - 8 x + 11 = 1

x^{2} - 6 x + 9 = 3

What are the solutions to the equation -16t^2-3t+70=0 ?
The solutions to the equation -16t^2-3t+70=0 are t=-35/16 ,t=2
Find the zeros of -16t^2-3t+70=0
The zeros of -16t^2-3t+70=0 are t=-35/16 ,t=2