What are the solutions to the equation (5x+1)(x-8)=0 ?

The solutions to the equation (5x+1)(x-8)=0 are x=-1/5 ,x=8

Find the zeros of (5x+1)(x-8)=0

The zeros of (5x+1)(x-8)=0 are x=-1/5 ,x=8

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(5 x + 1) (x - 8) = 0

x = - \frac{1}{5}, x = 8

Decimal Notation

x = - 0.2, x = 8

Solution steps

(5 x + 1) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 1 = 0 or x - 8 = 0

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = 8

2 = x^{2} - 2

x^{2} - 5 x - 31 = 5

x^{2} - 12 = - 3

x^{2} + 99 x - 37 = - 70

6 x^{2} - 11 x - 2 = 8

What are the solutions to the equation (5x+1)(x-8)=0 ?
The solutions to the equation (5x+1)(x-8)=0 are x=-1/5 ,x=8
Find the zeros of (5x+1)(x-8)=0
The zeros of (5x+1)(x-8)=0 are x=-1/5 ,x=8