What are the solutions to the equation 8(x^2-x)=-2 ?

The solutions to the equation 8(x^2-x)=-2 are x= 1/2

Find the zeros of 8(x^2-x)=-2

The zeros of 8(x^2-x)=-2 are x= 1/2

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8 (x^{2} - x) = - 2

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

8 (x^{2} - x) = - 2

Expand

8 (x^{2} - x) : 8 x^{2} - 8 x

8 x^{2} - 8 x = - 2

Move

2

to the left side

8 x^{2} - 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

(- 8)^{2} - 4 \cdot 8 \cdot 2 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 8}

x = \frac{- ( - 8 )}{2 \cdot 8}

\frac{- ( - 8 )}{2 \cdot 8} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

36 y^{2} + 24 - 85 = 0

1 + x = x^{2}

x^{2} + 19 x

x^{2} = 18 + 3 x

x^{2} + 4 = x^{2} \cdot 4

What are the solutions to the equation 8(x^2-x)=-2 ?
The solutions to the equation 8(x^2-x)=-2 are x= 1/2
Find the zeros of 8(x^2-x)=-2
The zeros of 8(x^2-x)=-2 are x= 1/2