What are the solutions to the equation 6x^2-2x+9=0 ?

The solutions to the equation 6x^2-2x+9=0 are x= 1/6+i(sqrt(53))/6 ,x= 1/6-i(sqrt(53))/6

Find the zeros of 6x^2-2x+9=0

The zeros of 6x^2-2x+9=0 are x= 1/6+i(sqrt(53))/6 ,x= 1/6-i(sqrt(53))/6

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6 x^{2} - 2 x + 9 = 0

x = \frac{1}{6} + i \frac{53}{6}, x = \frac{1}{6} - i \frac{53}{6}

Solution steps

6 x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 \cdot 9}{2 \cdot 6}

Simplify

(- 2)^{2} - 4 \cdot 6 \cdot 9 : 253 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 53 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 53 i}{2 \cdot 6}, x_{2} = \frac{- ( - 2 ) - 2 53 i}{2 \cdot 6}

x = \frac{- ( - 2 ) + 2 53 i}{2 \cdot 6} : \frac{1}{6} + i \frac{53}{6}

x = \frac{- ( - 2 ) - 2 53 i}{2 \cdot 6} : \frac{1}{6} - i \frac{53}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{53}{6}, x = \frac{1}{6} - i \frac{53}{6}

9 x^{2} = 16

(a - 3) (a - 4) = 0

10 x^{2} - x = 0

x, x^{2} = y^{2} - x y

x, x^{2} + m x + 4 = 0

What are the solutions to the equation 6x^2-2x+9=0 ?
The solutions to the equation 6x^2-2x+9=0 are x= 1/6+i(sqrt(53))/6 ,x= 1/6-i(sqrt(53))/6
Find the zeros of 6x^2-2x+9=0
The zeros of 6x^2-2x+9=0 are x= 1/6+i(sqrt(53))/6 ,x= 1/6-i(sqrt(53))/6