What are the solutions to the equation 11=7+17x-16x^2 ?

The solutions to the equation 11=7+17x-16x^2 are x=(17-sqrt(33))/(32),x=(17+sqrt(33))/(32)

Find the zeros of 11=7+17x-16x^2

The zeros of 11=7+17x-16x^2 are x=(17-sqrt(33))/(32),x=(17+sqrt(33))/(32)

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11 = 7 + 17 x - 16 x^{2}

x = \frac{17 - 33}{32}, x = \frac{17 + 33}{32}

Decimal Notation

x = 0.35173 \dots, x = 0.71076 \dots

Solution steps

11 = 7 + 17 x - 16 x^{2}

Switch sides

7 + 17 x - 16 x^{2} = 11

Move

11

to the left side

- 16 x^{2} + 17 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 16 ) ( - 4 )}{2 ( - 16 )}

1 7^{2} - 4 (- 16) (- 4) = 33

x_{1, 2} = \frac{- 17 \pm 33}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 17 + 33}{2 ( - 16 )}, x_{2} = \frac{- 17 - 33}{2 ( - 16 )}

x = \frac{- 17 + 33}{2 ( - 16 )} : \frac{17 - 33}{32}

x = \frac{- 17 - 33}{2 ( - 16 )} : \frac{17 + 33}{32}

The solutions to the quadratic equation are:

x = \frac{17 - 33}{32}, x = \frac{17 + 33}{32}

(- 16 t^{2} + 60 t + 180) = 0

x^{2} - \frac{4}{3} x = 0

2 x^{2} - 1 x - 3 = 0

7 x^{2} = - 21 x

2 x^{2} + 8 = 40

What are the solutions to the equation 11=7+17x-16x^2 ?
The solutions to the equation 11=7+17x-16x^2 are x=(17-sqrt(33))/(32),x=(17+sqrt(33))/(32)
Find the zeros of 11=7+17x-16x^2
The zeros of 11=7+17x-16x^2 are x=(17-sqrt(33))/(32),x=(17+sqrt(33))/(32)