What are the solutions to the equation -x^2+10x=25 ?

The solutions to the equation -x^2+10x=25 are x=5

Find the zeros of -x^2+10x=25

The zeros of -x^2+10x=25 are x=5

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- x^{2} + 10 x = 25

x = 5

Solution steps

- x^{2} + 10 x = 25

Move

25

to the left side

- x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 ( - 1 )}

x = \frac{- 10}{2 ( - 1 )}

\frac{- 10}{2 ( - 1 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

x^{2} + 58 = - 16 x

a^{2} - 12 a = 50

4 c^{2} - 9 c = 9

9 x + x (x - 4) = 12 - 19

4 x^{2} + 25 x = 21

What are the solutions to the equation -x^2+10x=25 ?
The solutions to the equation -x^2+10x=25 are x=5
Find the zeros of -x^2+10x=25
The zeros of -x^2+10x=25 are x=5