What are the solutions to the equation k^2-2k-5=0 ?

The solutions to the equation k^2-2k-5=0 are k=1+sqrt(6),k=1-sqrt(6)

Find the zeros of k^2-2k-5=0

The zeros of k^2-2k-5=0 are k=1+sqrt(6),k=1-sqrt(6)

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k^{2} - 2 k - 5 = 0

k = 1 + 6, k = 1 - 6

Decimal Notation

k = 3.44948 \dots, k = - 1.44948 \dots

Solution steps

k^{2} - 2 k - 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

k_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, k_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

k = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

k = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

k = 1 + 6, k = 1 - 6

(x + 6)^{2} = (x + 3)^{2} + x^{2}

- 2 x^{2} + 3 x + 14 = 0

6 y^{2} - y + 6 = 0

25 y^{2} + 40 y = - 16

x^{2} - 6 x + 12 = 41 + 12

What are the solutions to the equation k^2-2k-5=0 ?
The solutions to the equation k^2-2k-5=0 are k=1+sqrt(6),k=1-sqrt(6)
Find the zeros of k^2-2k-5=0
The zeros of k^2-2k-5=0 are k=1+sqrt(6),k=1-sqrt(6)