What are the solutions to the equation solvefor x,3x^2+5x-1=0 ?

The solutions to the equation solvefor x,3x^2+5x-1=0 are x=(-5+sqrt(37))/6 ,x=(-5-sqrt(37))/6

Find the zeros of solvefor x,3x^2+5x-1=0

The zeros of solvefor x,3x^2+5x-1=0 are x=(-5+sqrt(37))/6 ,x=(-5-sqrt(37))/6

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x, 3 x^{2} + 5 x - 1 = 0

x = \frac{- 5 + 37}{6}, x = \frac{- 5 - 37}{6}

Decimal Notation

x = 0.18046 \dots, x = - 1.84712 \dots

Solution steps

3 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 1) = 37

x_{1, 2} = \frac{- 5 \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 37}{2 \cdot 3}, x_{2} = \frac{- 5 - 37}{2 \cdot 3}

x = \frac{- 5 + 37}{2 \cdot 3} : \frac{- 5 + 37}{6}

x = \frac{- 5 - 37}{2 \cdot 3} : \frac{- 5 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 37}{6}, x = \frac{- 5 - 37}{6}

x^{2} - 3 x + 2 = 10

(n - 7)^{2} = 6

b^{2} + 15 b = 0

12 x^{2} = 11 x + 15

y (y - 2) = - 5

What are the solutions to the equation solvefor x,3x^2+5x-1=0 ?
The solutions to the equation solvefor x,3x^2+5x-1=0 are x=(-5+sqrt(37))/6 ,x=(-5-sqrt(37))/6
Find the zeros of solvefor x,3x^2+5x-1=0
The zeros of solvefor x,3x^2+5x-1=0 are x=(-5+sqrt(37))/6 ,x=(-5-sqrt(37))/6