What are the solutions to the equation (2x-5)^2-1=0 ?

The solutions to the equation (2x-5)^2-1=0 are x=3,x=2

Find the zeros of (2x-5)^2-1=0

The zeros of (2x-5)^2-1=0 are x=3,x=2

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(2 x - 5)^{2} - 1 = 0

x = 3, x = 2

Solution steps

(2 x - 5)^{2} - 1 = 0

Move

1

to the right side

(2 x - 5)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 1 : x = 3

Solve

2 x - 5 = - 1 : x = 2

The solutions to the quadratic equation are:

x = 3, x = 2

5 y^{2} - 2 = 9 y

x^{2} + 6 x + 15 = 6

x^{2} - x - 30 = 0

x, f (x - 2) = 3 x^{2} - 2

x, x^{2} = 16

What are the solutions to the equation (2x-5)^2-1=0 ?
The solutions to the equation (2x-5)^2-1=0 are x=3,x=2
Find the zeros of (2x-5)^2-1=0
The zeros of (2x-5)^2-1=0 are x=3,x=2