What are the solutions to the equation -6y^2+4y=-3y+2 ?

The solutions to the equation -6y^2+4y=-3y+2 are y= 1/2 ,y= 2/3

Find the zeros of -6y^2+4y=-3y+2

The zeros of -6y^2+4y=-3y+2 are y= 1/2 ,y= 2/3

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- 6 y^{2} + 4 y = - 3 y + 2

y = \frac{1}{2}, y = \frac{2}{3}

Decimal Notation

y = 0.5, y = 0.66666 \dots

Solution steps

- 6 y^{2} + 4 y = - 3 y + 2

Move

2

to the left side

- 6 y^{2} + 4 y - 2 = - 3 y

Move

3 y

to the left side

- 6 y^{2} + 7 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 6 ) ( - 2 )}{2 ( - 6 )}

7^{2} - 4 (- 6) (- 2) = 1

y_{1, 2} = \frac{- 7 \pm 1}{2 ( - 6 )}

Separate the solutions

y_{1} = \frac{- 7 + 1}{2 ( - 6 )}, y_{2} = \frac{- 7 - 1}{2 ( - 6 )}

y = \frac{- 7 + 1}{2 ( - 6 )} : \frac{1}{2}

y = \frac{- 7 - 1}{2 ( - 6 )} : \frac{2}{3}

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = \frac{2}{3}

4 a^{2} - 63 = 4 a

- 4 x^{2} + 5 = - 59

9 x^{2} + 5 x = 3

(3 x + 2) (x - 7) = 0

- 2 x^{2} + 8 x + 4 = 0

What are the solutions to the equation -6y^2+4y=-3y+2 ?
The solutions to the equation -6y^2+4y=-3y+2 are y= 1/2 ,y= 2/3
Find the zeros of -6y^2+4y=-3y+2
The zeros of -6y^2+4y=-3y+2 are y= 1/2 ,y= 2/3