What are the solutions to the equation 16= 4/3 (8x+3)34(8x+3) ?

The solutions to the equation 16= 4/3 (8x+3)34(8x+3) are x=(sqrt(6/17)-3)/8 ,x=(-sqrt(6/17)-3)/8

Find the zeros of 16= 4/3 (8x+3)34(8x+3)

The zeros of 16= 4/3 (8x+3)34(8x+3) are x=(sqrt(6/17)-3)/8 ,x=(-sqrt(6/17)-3)/8

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16 = \frac{4}{3} (8 x + 3) 34 (8 x + 3)

x = \frac{\frac{6}{17} - 3}{8}, x = \frac{- \frac{6}{17} - 3}{8}

Decimal Notation

x = - 0.30073 \dots, x = - 0.44926 \dots

Solution steps

16 = \frac{4}{3} (8 x + 3) \cdot 34 (8 x + 3)

Switch sides

\frac{4}{3} (8 x + 3) \cdot 34 (8 x + 3) = 16

Simplify

\frac{136}{3} (8 x + 3)^{2} = 16

Multiply both sides by

3

3 \cdot \frac{136}{3} (8 x + 3)^{2} = 16 \cdot 3

136 (8 x + 3)^{2} = 48

Divide both sides by

136

\frac{136 ( 8 x + 3 ) ^{2}}{136} = \frac{48}{136}

(8 x + 3)^{2} = \frac{6}{17}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

8 x + 3 = \frac{6}{17} : x = \frac{\frac{6}{17} - 3}{8}

Solve

8 x + 3 = - \frac{6}{17} : x = \frac{- \frac{6}{17} - 3}{8}

The solutions to the quadratic equation are:

x = \frac{\frac{6}{17} - 3}{8}, x = \frac{- \frac{6}{17} - 3}{8}

x^{2} = 3 (x + 6)

x^{2} + 4 x - 12 = 9

4 t^{2} = 64

x^{2} - \frac{16}{256} = 0

2 x^{2} + 9 = - 4

What are the solutions to the equation 16= 4/3 (8x+3)34(8x+3) ?
The solutions to the equation 16= 4/3 (8x+3)34(8x+3) are x=(sqrt(6/17)-3)/8 ,x=(-sqrt(6/17)-3)/8
Find the zeros of 16= 4/3 (8x+3)34(8x+3)
The zeros of 16= 4/3 (8x+3)34(8x+3) are x=(sqrt(6/17)-3)/8 ,x=(-sqrt(6/17)-3)/8