What are the solutions to the equation (3x-8)(6x-1)=3 ?

The solutions to the equation (3x-8)(6x-1)=3 are x=(17+sqrt(249))/(12),x=(17-sqrt(249))/(12)

Find the zeros of (3x-8)(6x-1)=3

The zeros of (3x-8)(6x-1)=3 are x=(17+sqrt(249))/(12),x=(17-sqrt(249))/(12)

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(3 x - 8) (6 x - 1) = 3

x = \frac{17 + 249}{12}, x = \frac{17 - 249}{12}

Decimal Notation

x = 2.73164 \dots, x = 0.10168 \dots

Solution steps

(3 x - 8) (6 x - 1) = 3

Expand

(3 x - 8) (6 x - 1) : 18 x^{2} - 51 x + 8

18 x^{2} - 51 x + 8 = 3

Move

3

to the left side

18 x^{2} - 51 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 51 ) \pm ( - 51 ) ^{2} - 4 \cdot 18 \cdot 5}{2 \cdot 18}

(- 51)^{2} - 4 \cdot 18 \cdot 5 = 3249

x_{1, 2} = \frac{- ( - 51 ) \pm 3 249}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 51 ) + 3 249}{2 \cdot 18}, x_{2} = \frac{- ( - 51 ) - 3 249}{2 \cdot 18}

x = \frac{- ( - 51 ) + 3 249}{2 \cdot 18} : \frac{17 + 249}{12}

x = \frac{- ( - 51 ) - 3 249}{2 \cdot 18} : \frac{17 - 249}{12}

The solutions to the quadratic equation are:

x = \frac{17 + 249}{12}, x = \frac{17 - 249}{12}

2 a^{2} = x^{2}

0.2 (55 - x) = x^{2}

3 x^{2} - 4 x + 2 = 3

5 x^{2} = 14 x + 24

x^{2} = \frac{8}{9}

What are the solutions to the equation (3x-8)(6x-1)=3 ?
The solutions to the equation (3x-8)(6x-1)=3 are x=(17+sqrt(249))/(12),x=(17-sqrt(249))/(12)
Find the zeros of (3x-8)(6x-1)=3
The zeros of (3x-8)(6x-1)=3 are x=(17+sqrt(249))/(12),x=(17-sqrt(249))/(12)