What are the solutions to the equation -5x^2+43x-56=0 ?

The solutions to the equation -5x^2+43x-56=0 are x= 8/5 ,x=7

Find the zeros of -5x^2+43x-56=0

The zeros of -5x^2+43x-56=0 are x= 8/5 ,x=7

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- 5 x^{2} + 43 x - 56 = 0

x = \frac{8}{5}, x = 7

Decimal Notation

x = 1.6, x = 7

Solution steps

- 5 x^{2} + 43 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 43 \pm 4 3 ^{2} - 4 ( - 5 ) ( - 56 )}{2 ( - 5 )}

4 3^{2} - 4 (- 5) (- 56) = 27

x_{1, 2} = \frac{- 43 \pm 27}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 43 + 27}{2 ( - 5 )}, x_{2} = \frac{- 43 - 27}{2 ( - 5 )}

x = \frac{- 43 + 27}{2 ( - 5 )} : \frac{8}{5}

x = \frac{- 43 - 27}{2 ( - 5 )} : 7

The solutions to the quadratic equation are:

x = \frac{8}{5}, x = 7

- 2 x^{2} - x - 3 = 0

- 4 p^{2} - 12 p + 3 = 0

x^{2} - 15 x - 34 = 0

x^{2} + \frac{1}{3} x - 10 = 0

b^{2} - 3 b - 40 = 0

What are the solutions to the equation -5x^2+43x-56=0 ?
The solutions to the equation -5x^2+43x-56=0 are x= 8/5 ,x=7
Find the zeros of -5x^2+43x-56=0
The zeros of -5x^2+43x-56=0 are x= 8/5 ,x=7