What are the solutions to the equation 4^2=2^2+b^2 ?

The solutions to the equation 4^2=2^2+b^2 are b=2sqrt(3),b=-2sqrt(3)

Find the zeros of 4^2=2^2+b^2

The zeros of 4^2=2^2+b^2 are b=2sqrt(3),b=-2sqrt(3)

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4^{2} = 2^{2} + b^{2}

b = 23, b = - 23

Decimal Notation

b = 3.46410 \dots, b = - 3.46410 \dots

Solution steps

4^{2} = 2^{2} + b^{2}

Switch sides

2^{2} + b^{2} = 4^{2}

Move

2^{2}

to the right side

b^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 12, b = - 12

12 = 23

- 12 = - 23

b = 23, b = - 23

(5 x - 4)^{2} - 1 = 0

1.5 w (w + 3) = 0.6 w

a = (\frac{5 + 10}{5}) \cdot x^{2}

x, g = x^{2} - 4 xg (2 - x)

9 x^{2} - 16 x = 4

What are the solutions to the equation 4^2=2^2+b^2 ?
The solutions to the equation 4^2=2^2+b^2 are b=2sqrt(3),b=-2sqrt(3)
Find the zeros of 4^2=2^2+b^2
The zeros of 4^2=2^2+b^2 are b=2sqrt(3),b=-2sqrt(3)