What are the solutions to the equation completesquare v^2+2v ?

The solutions to the equation completesquare v^2+2v are (v+1)^2-1

Find the zeros of completesquare v^2+2v

The zeros of completesquare v^2+2v are (v+1)^2-1

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complete the square

v^{2} + 2 v

(v + 1)^{2} - 1

Solution steps

v^{2} + 2 v

Write

v^{2} + 2 v

in the form:

x^{2} + 2 a x + a^{2}

2 a = 2 : a = 1

Add and subtract

1^{2}

v^{2} + 2 v + 1^{2} - 1^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

v^{2} + 2 v + 1^{2} = (v + 1)^{2}

(v + 1)^{2} - 1^{2}

Simplify

(v + 1)^{2} - 1

3 (v + 3)^{2} = 63

- 2 x^{2} + 24 x + 312 = 0

x, x^{2} + y^{2} = k y

x^{2} + x + 6

9 x^{2} + 6 x - 2 = 7

What are the solutions to the equation completesquare v^2+2v ?
The solutions to the equation completesquare v^2+2v are (v+1)^2-1
Find the zeros of completesquare v^2+2v
The zeros of completesquare v^2+2v are (v+1)^2-1