What are the solutions to the equation -7=5x^2-4x-7 ?

The solutions to the equation -7=5x^2-4x-7 are x= 4/5 ,x=0

Find the zeros of -7=5x^2-4x-7

The zeros of -7=5x^2-4x-7 are x= 4/5 ,x=0

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- 7 = 5 x^{2} - 4 x - 7

x = \frac{4}{5}, x = 0

Decimal Notation

x = 0.8, x = 0

Solution steps

- 7 = 5 x^{2} - 4 x - 7

Switch sides

5 x^{2} - 4 x - 7 = - 7

Move

7

to the left side

5 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 5}

x = \frac{- ( - 4 ) + 4}{2 \cdot 5} : \frac{4}{5}

x = \frac{- ( - 4 ) - 4}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = 0

x^{2} - 15 = 10

x^{2} + x - 12 = x + 4 x + 4

3 x^{2} - 486 = 0

x, 3 x^{2} - 12 = 0

49 x^{2} - 70 + 25 = 0

What are the solutions to the equation -7=5x^2-4x-7 ?
The solutions to the equation -7=5x^2-4x-7 are x= 4/5 ,x=0
Find the zeros of -7=5x^2-4x-7
The zeros of -7=5x^2-4x-7 are x= 4/5 ,x=0