What are the solutions to the equation 12x^2-7x-1=0 ?

The solutions to the equation 12x^2-7x-1=0 are x=(7+sqrt(97))/(24),x=(7-sqrt(97))/(24)

Find the zeros of 12x^2-7x-1=0

The zeros of 12x^2-7x-1=0 are x=(7+sqrt(97))/(24),x=(7-sqrt(97))/(24)

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12 x^{2} - 7 x - 1 = 0

x = \frac{7 + 97}{24}, x = \frac{7 - 97}{24}

Decimal Notation

x = 0.70203 \dots, x = - 0.11870 \dots

Solution steps

12 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 12 ( - 1 )}{2 \cdot 12}

(- 7)^{2} - 4 \cdot 12 (- 1) = 97

x_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 12}, x_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 12}

x = \frac{- ( - 7 ) + 97}{2 \cdot 12} : \frac{7 + 97}{24}

x = \frac{- ( - 7 ) - 97}{2 \cdot 12} : \frac{7 - 97}{24}

The solutions to the quadratic equation are:

x = \frac{7 + 97}{24}, x = \frac{7 - 97}{24}

(x) = 3 x^{2} - 6 x + 2

8 x^{2} + 2 x - 3 = 0

3 x^{2} + \frac{7}{5} = 2 x

36 + b^{2} = 100

12 x^{2} + 10 x - 8 = 0

What are the solutions to the equation 12x^2-7x-1=0 ?
The solutions to the equation 12x^2-7x-1=0 are x=(7+sqrt(97))/(24),x=(7-sqrt(97))/(24)
Find the zeros of 12x^2-7x-1=0
The zeros of 12x^2-7x-1=0 are x=(7+sqrt(97))/(24),x=(7-sqrt(97))/(24)