What are the solutions to the equation y^2+10y-7=0 ?

The solutions to the equation y^2+10y-7=0 are y=-5+4sqrt(2),y=-5-4sqrt(2)

Find the zeros of y^2+10y-7=0

The zeros of y^2+10y-7=0 are y=-5+4sqrt(2),y=-5-4sqrt(2)

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y^{2} + 10 y - 7 = 0

y = - 5 + 42, y = - 5 - 42

Decimal Notation

y = 0.65685 \dots, y = - 10.65685 \dots

Solution steps

y^{2} + 10 y - 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 7) = 82

y_{1, 2} = \frac{- 10 \pm 8 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 8 2}{2 \cdot 1}, y_{2} = \frac{- 10 - 8 2}{2 \cdot 1}

y = \frac{- 10 + 8 2}{2 \cdot 1} : - 5 + 42

y = \frac{- 10 - 8 2}{2 \cdot 1} : - 5 - 42

The solutions to the quadratic equation are:

y = - 5 + 42, y = - 5 - 42

2 y^{2} - y = y + 12

x^{2} - 3 x - 8 = 2

x^{2} - 82 = 0

x, f = x^{2} - 3 x + 1 f (1)

x^{2} + x^{2} = 14

What are the solutions to the equation y^2+10y-7=0 ?
The solutions to the equation y^2+10y-7=0 are y=-5+4sqrt(2),y=-5-4sqrt(2)
Find the zeros of y^2+10y-7=0
The zeros of y^2+10y-7=0 are y=-5+4sqrt(2),y=-5-4sqrt(2)