What are the solutions to the equation -x^2+48x-575=0 ?

The solutions to the equation -x^2+48x-575=0 are x=23,x=25

Find the zeros of -x^2+48x-575=0

The zeros of -x^2+48x-575=0 are x=23,x=25

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- x^{2} + 48 x - 575 = 0

x = 23, x = 25

Solution steps

- x^{2} + 48 x - 575 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 1 ) ( - 575 )}{2 ( - 1 )}

4 8^{2} - 4 (- 1) (- 575) = 2

x_{1, 2} = \frac{- 48 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 48 + 2}{2 ( - 1 )}, x_{2} = \frac{- 48 - 2}{2 ( - 1 )}

x = \frac{- 48 + 2}{2 ( - 1 )} : 23

x = \frac{- 48 - 2}{2 ( - 1 )} : 25

The solutions to the quadratic equation are:

x = 23, x = 25

76 = \frac{1}{2} (h (2 h + 3))

3 x (2 x + 2 x) = x (5 x - 5)

8 x^{2} - 6 b x - 3 b^{2} = 0

0 = - 2 x^{2} + 20 x + 48

10 + 3 x - x^{2} = 0

What are the solutions to the equation -x^2+48x-575=0 ?
The solutions to the equation -x^2+48x-575=0 are x=23,x=25
Find the zeros of -x^2+48x-575=0
The zeros of -x^2+48x-575=0 are x=23,x=25