What are the solutions to the equation 2x^2-5bx-3b^2=0 ?

The solutions to the equation 2x^2-5bx-3b^2=0 are x=3b,x=-b/2

Find the zeros of 2x^2-5bx-3b^2=0

The zeros of 2x^2-5bx-3b^2=0 are x=3b,x=-b/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 5 b x - 3 b^{2} = 0

x = 3 b, x = - \frac{b}{2}

Solution steps

2 x^{2} - 5 b x - 3 b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 b ) \pm ( - 5 b ) ^{2} - 4 \cdot 2 ( - 3 b ^{2} )}{2 \cdot 2}

Simplify

(- 5 b)^{2} - 4 \cdot 2 (- 3 b^{2}) : 7 b

x_{1, 2} = \frac{- ( - 5 b ) \pm 7 b}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 b ) + 7 b}{2 \cdot 2}, x_{2} = \frac{- ( - 5 b ) - 7 b}{2 \cdot 2}

x = \frac{- ( - 5 b ) + 7 b}{2 \cdot 2} : 3 b

x = \frac{- ( - 5 b ) - 7 b}{2 \cdot 2} : - \frac{b}{2}

The solutions to the quadratic equation are:

x = 3 b, x = - \frac{b}{2}

2 f (a) = 5 x^{2} - x + 2

n (n + 1) = 240

- 0.06 x^{2} + 4 x - 35 = 0

16 9^{2} = 12 5^{2} + x^{2}

(x - 2)^{2} = 5 - (x - 1)^{2}

What are the solutions to the equation 2x^2-5bx-3b^2=0 ?
The solutions to the equation 2x^2-5bx-3b^2=0 are x=3b,x=-b/2
Find the zeros of 2x^2-5bx-3b^2=0
The zeros of 2x^2-5bx-3b^2=0 are x=3b,x=-b/2