What are the solutions to the equation -3x^2+6x+12=0 ?

The solutions to the equation -3x^2+6x+12=0 are x=1-sqrt(5),x=1+sqrt(5)

Find the zeros of -3x^2+6x+12=0

The zeros of -3x^2+6x+12=0 are x=1-sqrt(5),x=1+sqrt(5)

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- 3 x^{2} + 6 x + 12 = 0

x = 1 - 5, x = 1 + 5

Decimal Notation

x = - 1.23606 \dots, x = 3.23606 \dots

Solution steps

- 3 x^{2} + 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 12}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 12 = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6 5}{2 ( - 3 )}

x = \frac{- 6 + 6 5}{2 ( - 3 )} : 1 - 5

x = \frac{- 6 - 6 5}{2 ( - 3 )} : 1 + 5

The solutions to the quadratic equation are:

x = 1 - 5, x = 1 + 5

14 n^{2} + 12 n + 3 = 6 n^{2} + 4 n + 7

4 x (x - 1) = 3 x - 2

x (5 - x) = 4

y^{2} + 13 y + 36 = 0

w^{2} - 2 w + 26 = 93

What are the solutions to the equation -3x^2+6x+12=0 ?
The solutions to the equation -3x^2+6x+12=0 are x=1-sqrt(5),x=1+sqrt(5)
Find the zeros of -3x^2+6x+12=0
The zeros of -3x^2+6x+12=0 are x=1-sqrt(5),x=1+sqrt(5)