What are the solutions to the equation x^2+144x=0 ?

The solutions to the equation x^2+144x=0 are x=0,x=-144

Find the zeros of x^2+144x=0

The zeros of x^2+144x=0 are x=0,x=-144

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x^{2} + 144 x = 0

x = 0, x = - 144

Solution steps

x^{2} + 144 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

14 4^{2} - 4 \cdot 1 \cdot 0 = 144

x_{1, 2} = \frac{- 144 \pm 144}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 144 + 144}{2 \cdot 1}, x_{2} = \frac{- 144 - 144}{2 \cdot 1}

x = \frac{- 144 + 144}{2 \cdot 1} : 0

x = \frac{- 144 - 144}{2 \cdot 1} : - 144

The solutions to the quadratic equation are:

x = 0, x = - 144

x, x^{2} - 2 y - 1 = C

3 x (x - 3) = 8 x^{2} - 11 x

y, y^{2} = x^{2} - 1

2 x^{2} - 13 x + 7 = 0

x (x - 1) - 2 = 0

What are the solutions to the equation x^2+144x=0 ?
The solutions to the equation x^2+144x=0 are x=0,x=-144
Find the zeros of x^2+144x=0
The zeros of x^2+144x=0 are x=0,x=-144