What are the solutions to the equation x^2-x-12=8 ?

The solutions to the equation x^2-x-12=8 are x=5,x=-4

Find the zeros of x^2-x-12=8

The zeros of x^2-x-12=8 are x=5,x=-4

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x^{2} - x - 12 = 8

x = 5, x = - 4

Solution steps

x^{2} - x - 12 = 8

Move

8

to the left side

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

5 x^{2} - 3 x - 7 = 0

- x - 1 = x^{2} - 5

(2 x - 45)^{2} = (x - 21)^{2}

2 x^{2} + x + 5 = 11

x^{2} - 15083 x - 305430 = 0

What are the solutions to the equation x^2-x-12=8 ?
The solutions to the equation x^2-x-12=8 are x=5,x=-4
Find the zeros of x^2-x-12=8
The zeros of x^2-x-12=8 are x=5,x=-4