What are the solutions to the equation 15=7+23t-16t^2 ?

The solutions to the equation 15=7+23t-16t^2 are t=(23-sqrt(17))/(32),t=(23+sqrt(17))/(32)

Find the zeros of 15=7+23t-16t^2

The zeros of 15=7+23t-16t^2 are t=(23-sqrt(17))/(32),t=(23+sqrt(17))/(32)

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15 = 7 + 23 t - 16 t^{2}

t = \frac{23 - 17}{32}, t = \frac{23 + 17}{32}

Decimal Notation

t = 0.58990 \dots, t = 0.84759 \dots

Solution steps

15 = 7 + 23 t - 16 t^{2}

Switch sides

7 + 23 t - 16 t^{2} = 15

Move

15

to the left side

- 16 t^{2} + 23 t - 8 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 ( - 16 ) ( - 8 )}{2 ( - 16 )}

2 3^{2} - 4 (- 16) (- 8) = 17

t_{1, 2} = \frac{- 23 \pm 17}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 23 + 17}{2 ( - 16 )}, t_{2} = \frac{- 23 - 17}{2 ( - 16 )}

t = \frac{- 23 + 17}{2 ( - 16 )} : \frac{23 - 17}{32}

t = \frac{- 23 - 17}{2 ( - 16 )} : \frac{23 + 17}{32}

The solutions to the quadratic equation are:

t = \frac{23 - 17}{32}, t = \frac{23 + 17}{32}

x^{2} + 10 x - 8 = 0

y^{2} - 6 a y + (9 a^{2} - 4) = 0

(x - 7)^{2} = (3 x + 4) (x - 6) + 1

x, x^{2} - 81 = 0

(x - 2)^{2} + (x + 2)^{2} = x^{2}

What are the solutions to the equation 15=7+23t-16t^2 ?
The solutions to the equation 15=7+23t-16t^2 are t=(23-sqrt(17))/(32),t=(23+sqrt(17))/(32)
Find the zeros of 15=7+23t-16t^2
The zeros of 15=7+23t-16t^2 are t=(23-sqrt(17))/(32),t=(23+sqrt(17))/(32)