What are the solutions to the equation c^2+c-7=0 ?

The solutions to the equation c^2+c-7=0 are c=(-1+sqrt(29))/2 ,c=(-1-sqrt(29))/2

Find the zeros of c^2+c-7=0

The zeros of c^2+c-7=0 are c=(-1+sqrt(29))/2 ,c=(-1-sqrt(29))/2

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c^{2} + c - 7 = 0

c = \frac{- 1 + 29}{2}, c = \frac{- 1 - 29}{2}

Decimal Notation

c = 2.19258 \dots, c = - 3.19258 \dots

Solution steps

c^{2} + c - 7 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 7) = 29

c_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 1 + 29}{2 \cdot 1}, c_{2} = \frac{- 1 - 29}{2 \cdot 1}

c = \frac{- 1 + 29}{2 \cdot 1} : \frac{- 1 + 29}{2}

c = \frac{- 1 - 29}{2 \cdot 1} : \frac{- 1 - 29}{2}

The solutions to the quadratic equation are:

c = \frac{- 1 + 29}{2}, c = \frac{- 1 - 29}{2}

x^{2} - 3 = x - 1

1 = (x - 1)^{2}

0.085 x^{2} - 5 x + 40 = 0

x^{2} - 8 x - 300 = 0

22 = 27 - 2 Q^{2}

What are the solutions to the equation c^2+c-7=0 ?
The solutions to the equation c^2+c-7=0 are c=(-1+sqrt(29))/2 ,c=(-1-sqrt(29))/2
Find the zeros of c^2+c-7=0
The zeros of c^2+c-7=0 are c=(-1+sqrt(29))/2 ,c=(-1-sqrt(29))/2