What are the solutions to the equation 480=5(12-0.6x)^2+3x^2 ?

The solutions to the equation 480=5(12-0.6x)^2+3x^2 are x=(96)/(9.6),x=(48)/(9.6)

Find the zeros of 480=5(12-0.6x)^2+3x^2

The zeros of 480=5(12-0.6x)^2+3x^2 are x=(96)/(9.6),x=(48)/(9.6)

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480 = 5 (12 - 0.6 x)^{2} + 3 x^{2}

x = \frac{96}{9.6}, x = \frac{48}{9.6}

Decimal Notation

x = 10, x = 5

Solution steps

480 = 5 (12 - 0.6 x)^{2} + 3 x^{2}

Expand

5 (12 - 0.6 x)^{2} + 3 x^{2} : 720 - 72 x + 4.8 x^{2}

480 = 720 - 72 x + 4.8 x^{2}

Switch sides

720 - 72 x + 4.8 x^{2} = 480

Move

480

to the left side

4.8 x^{2} - 72 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 4.8 \cdot 240}{2 \cdot 4.8}

(- 72)^{2} - 4 \cdot 4.8 \cdot 240 = 24

x_{1, 2} = \frac{- ( - 72 ) \pm 24}{2 \cdot 4.8}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 24}{2 \cdot 4.8}, x_{2} = \frac{- ( - 72 ) - 24}{2 \cdot 4.8}

x = \frac{- ( - 72 ) + 24}{2 \cdot 4.8} : \frac{96}{9.6}

x = \frac{- ( - 72 ) - 24}{2 \cdot 4.8} : \frac{48}{9.6}

The solutions to the quadratic equation are:

x = \frac{96}{9.6}, x = \frac{48}{9.6}

4 x^{2} + 5 - 8 x = 0

(1 - x^{2}) = 9 x^{2}

3 a^{2} + 16 a + 5 = 0

x^{2} + 2 x^{2} = 1 0^{2}

7 + 5 x - x^{2}

What are the solutions to the equation 480=5(12-0.6x)^2+3x^2 ?
The solutions to the equation 480=5(12-0.6x)^2+3x^2 are x=(96)/(9.6),x=(48)/(9.6)
Find the zeros of 480=5(12-0.6x)^2+3x^2
The zeros of 480=5(12-0.6x)^2+3x^2 are x=(96)/(9.6),x=(48)/(9.6)