What are the solutions to the equation (x-3)^2=18 ?

The solutions to the equation (x-3)^2=18 are x=3sqrt(2)+3,x=-3sqrt(2)+3

Find the zeros of (x-3)^2=18

The zeros of (x-3)^2=18 are x=3sqrt(2)+3,x=-3sqrt(2)+3

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(x - 3)^{2} = 18

x = 32 + 3, x = - 32 + 3

Decimal Notation

x = 7.24264 \dots, x = - 1.24264 \dots

Solution steps

(x - 3)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 18 : x = 32 + 3

Solve

x - 3 = - 18 : x = - 32 + 3

The solutions to the quadratic equation are:

x = 32 + 3, x = - 32 + 3

x^{2} + 2 - 2 = 0

x^{2} = 7^{2} + 3^{2}

x, x^{2} - 10 x y + y^{2} = 10

(3 x + 1)^{2} = (5 x + 5) (x + 2)

x^{2} + 8 x = a + b x^{2} + c (x + 1) (x + 3)

What are the solutions to the equation (x-3)^2=18 ?
The solutions to the equation (x-3)^2=18 are x=3sqrt(2)+3,x=-3sqrt(2)+3
Find the zeros of (x-3)^2=18
The zeros of (x-3)^2=18 are x=3sqrt(2)+3,x=-3sqrt(2)+3