What are the solutions to the equation -1/2 h(2h+3)=0 ?

The solutions to the equation -1/2 h(2h+3)=0 are h=0,h=-3/2

Find the zeros of -1/2 h(2h+3)=0

The zeros of -1/2 h(2h+3)=0 are h=0,h=-3/2

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- \frac{1}{2} h (2 h + 3) = 0

h = 0, h = - \frac{3}{2}

Decimal Notation

h = 0, h = - 1.5

Solution steps

- \frac{1}{2} h (2 h + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

h = 0 or 2 h + 3 = 0

Solve

2 h + 3 = 0 : h = - \frac{3}{2}

The solutions to the quadratic equation are:

h = 0, h = - \frac{3}{2}

(x^{2} - 2 x + 1) = 0

3 p (p + 2) = p (p - 4)

a = 2 x + 2 x^{2}

0 = 5 - x^{2}

y, y + 10 y^{2} = 24 t

What are the solutions to the equation -1/2 h(2h+3)=0 ?
The solutions to the equation -1/2 h(2h+3)=0 are h=0,h=-3/2
Find the zeros of -1/2 h(2h+3)=0
The zeros of -1/2 h(2h+3)=0 are h=0,h=-3/2