What are the solutions to the equation s^2+4s-21=0 ?

The solutions to the equation s^2+4s-21=0 are s=3,s=-7

Find the zeros of s^2+4s-21=0

The zeros of s^2+4s-21=0 are s=3,s=-7

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s^{2} + 4 s - 21 = 0

s = 3, s = - 7

Solution steps

s^{2} + 4 s - 21 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

s_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 10}{2 \cdot 1}, s_{2} = \frac{- 4 - 10}{2 \cdot 1}

s = \frac{- 4 + 10}{2 \cdot 1} : 3

s = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

s = 3, s = - 7

17 x - 16 > 18

5 a^{2} b^{2} + 10 ab + 25 a

\frac{3}{5} - \frac{2}{3}

\frac{1}{i} + \frac{4}{i ^{3}}

2 (x + 2)^{2} - 4 = 28

What are the solutions to the equation s^2+4s-21=0 ?
The solutions to the equation s^2+4s-21=0 are s=3,s=-7
Find the zeros of s^2+4s-21=0
The zeros of s^2+4s-21=0 are s=3,s=-7