What are the solutions to the equation 6x^2+8x-8=0 ?

The solutions to the equation 6x^2+8x-8=0 are x= 2/3 ,x=-2

Find the zeros of 6x^2+8x-8=0

The zeros of 6x^2+8x-8=0 are x= 2/3 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 8 x - 8 = 0

x = \frac{2}{3}, x = - 2

Decimal Notation

x = 0.66666 \dots, x = - 2

Solution steps

6 x^{2} + 8 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 6 ( - 8 )}{2 \cdot 6}

8^{2} - 4 \cdot 6 (- 8) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 6}, x_{2} = \frac{- 8 - 16}{2 \cdot 6}

x = \frac{- 8 + 16}{2 \cdot 6} : \frac{2}{3}

x = \frac{- 8 - 16}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 2

9 x^{2} - 30 x + 29 = 0

y, x^{2} - y^{2} = 0

4 x^{2} + 10 x = 36

y^{2} - 14 y + 42 = 0

h^{2} + 3 h = 30

What are the solutions to the equation 6x^2+8x-8=0 ?
The solutions to the equation 6x^2+8x-8=0 are x= 2/3 ,x=-2
Find the zeros of 6x^2+8x-8=0
The zeros of 6x^2+8x-8=0 are x= 2/3 ,x=-2