What are the solutions to the equation y^2-14y+46=0 ?

The solutions to the equation y^2-14y+46=0 are y=7+sqrt(3),y=7-sqrt(3)

Find the zeros of y^2-14y+46=0

The zeros of y^2-14y+46=0 are y=7+sqrt(3),y=7-sqrt(3)

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y^{2} - 14 y + 46 = 0

y = 7 + 3, y = 7 - 3

Decimal Notation

y = 8.73205 \dots, y = 5.26794 \dots

Solution steps

y^{2} - 14 y + 46 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 46}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 46 = 23

y_{1, 2} = \frac{- ( - 14 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 3}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 2 3}{2 \cdot 1}

y = \frac{- ( - 14 ) + 2 3}{2 \cdot 1} : 7 + 3

y = \frac{- ( - 14 ) - 2 3}{2 \cdot 1} : 7 - 3

The solutions to the quadratic equation are:

y = 7 + 3, y = 7 - 3

55^{2} + x^{2} = 2 x^{2}

g (n) = n^{2} + 4 n, g (g (n))

x^{2} + 19 x - 42 = 0

200 = - 2 x^{2} + 40 x + 100

3 x^{2} + 14 = 8

What are the solutions to the equation y^2-14y+46=0 ?
The solutions to the equation y^2-14y+46=0 are y=7+sqrt(3),y=7-sqrt(3)
Find the zeros of y^2-14y+46=0
The zeros of y^2-14y+46=0 are y=7+sqrt(3),y=7-sqrt(3)