What are the solutions to the equation ax^2-2x+4=0 ?

The solutions to the equation ax^2-2x+4=0 are x=(1+sqrt(-4a+1))/a ,x=(1-sqrt(-4a+1))/a ;\quad a\ne 0

Find the zeros of ax^2-2x+4=0

The zeros of ax^2-2x+4=0 are x=(1+sqrt(-4a+1))/a ,x=(1-sqrt(-4a+1))/a ;\quad a\ne 0

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a x^{2} - 2 x + 4 = 0

x = \frac{1 + - 4 a + 1}{a}, x = \frac{1 - - 4 a + 1}{a}; a \neq = 0

Solution steps

a x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 a \cdot 4}{2 a}

Simplify

(- 2)^{2} - 4 a \cdot 4 : 2 1 - 4 a

x_{1, 2} = \frac{- ( - 2 ) \pm 2 1 - 4 a}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 1 - 4 a}{2 a}, x_{2} = \frac{- ( - 2 ) - 2 1 - 4 a}{2 a}

x = \frac{- ( - 2 ) + 2 1 - 4 a}{2 a} : \frac{1 + - 4 a + 1}{a}

x = \frac{- ( - 2 ) - 2 1 - 4 a}{2 a} : \frac{1 - - 4 a + 1}{a}

The solutions to the quadratic equation are:

x = \frac{1 + - 4 a + 1}{a}, x = \frac{1 - - 4 a + 1}{a}; a \neq = 0

x, f = x^{2} - k x + k^{2}

2 y^{2} + 10 y - 5 = 0

6 x^{2} + 5 x - 6 = 0

r^{2} - 9 r - 10 = 0

- x^{2} - 36 = 0

What are the solutions to the equation ax^2-2x+4=0 ?
The solutions to the equation ax^2-2x+4=0 are x=(1+sqrt(-4a+1))/a ,x=(1-sqrt(-4a+1))/a ;\quad a\ne 0
Find the zeros of ax^2-2x+4=0
The zeros of ax^2-2x+4=0 are x=(1+sqrt(-4a+1))/a ,x=(1-sqrt(-4a+1))/a ;\quad a\ne 0