What are the solutions to the equation 3n^2+10n+5=7 ?

The solutions to the equation 3n^2+10n+5=7 are n=(-5+sqrt(31))/3 ,n=-(5+sqrt(31))/3

Find the zeros of 3n^2+10n+5=7

The zeros of 3n^2+10n+5=7 are n=(-5+sqrt(31))/3 ,n=-(5+sqrt(31))/3

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3 n^{2} + 10 n + 5 = 7

n = \frac{- 5 + 31}{3}, n = - \frac{5 + 31}{3}

Decimal Notation

n = 0.18925 \dots, n = - 3.52258 \dots

Solution steps

3 n^{2} + 10 n + 5 = 7

Move

7

to the left side

3 n^{2} + 10 n - 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 2) = 231

n_{1, 2} = \frac{- 10 \pm 2 31}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 10 + 2 31}{2 \cdot 3}, n_{2} = \frac{- 10 - 2 31}{2 \cdot 3}

n = \frac{- 10 + 2 31}{2 \cdot 3} : \frac{- 5 + 31}{3}

n = \frac{- 10 - 2 31}{2 \cdot 3} : - \frac{5 + 31}{3}

The solutions to the quadratic equation are:

n = \frac{- 5 + 31}{3}, n = - \frac{5 + 31}{3}

3 x (x + 8) = - 2

\frac{x + 1}{2} = x^{2}

x^{2} + x = - 9

x^{2} + 21 = 5

x^{2} + 7 x - 13 = 0

What are the solutions to the equation 3n^2+10n+5=7 ?
The solutions to the equation 3n^2+10n+5=7 are n=(-5+sqrt(31))/3 ,n=-(5+sqrt(31))/3
Find the zeros of 3n^2+10n+5=7
The zeros of 3n^2+10n+5=7 are n=(-5+sqrt(31))/3 ,n=-(5+sqrt(31))/3