What are the solutions to the equation 3+20x-5x^2=0 ?

The solutions to the equation 3+20x-5x^2=0 are x=-(-10+sqrt(115))/5 ,x=(10+sqrt(115))/5

Find the zeros of 3+20x-5x^2=0

The zeros of 3+20x-5x^2=0 are x=-(-10+sqrt(115))/5 ,x=(10+sqrt(115))/5

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3 + 20 x - 5 x^{2} = 0

x = - \frac{- 10 + 115}{5}, x = \frac{10 + 115}{5}

Decimal Notation

x = - 0.14476 \dots, x = 4.14476 \dots

Solution steps

3 + 20 x - 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 20 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 5 ) \cdot 3}{2 ( - 5 )}

2 0^{2} - 4 (- 5) \cdot 3 = 2115

x_{1, 2} = \frac{- 20 \pm 2 115}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 20 + 2 115}{2 ( - 5 )}, x_{2} = \frac{- 20 - 2 115}{2 ( - 5 )}

x = \frac{- 20 + 2 115}{2 ( - 5 )} : - \frac{- 10 + 115}{5}

x = \frac{- 20 - 2 115}{2 ( - 5 )} : \frac{10 + 115}{5}

The solutions to the quadratic equation are:

x = - \frac{- 10 + 115}{5}, x = \frac{10 + 115}{5}

3 x^{2} - 5 x - 2 = 0

700 = \frac{( 8 ( g ^{2} ) )}{800}

(- x - 3) (x + 4) - 5 (x + 4) = 0

w^{2} + 3 w - 18 = 0

4 x^{2} + 25 x = - 25

What are the solutions to the equation 3+20x-5x^2=0 ?
The solutions to the equation 3+20x-5x^2=0 are x=-(-10+sqrt(115))/5 ,x=(10+sqrt(115))/5
Find the zeros of 3+20x-5x^2=0
The zeros of 3+20x-5x^2=0 are x=-(-10+sqrt(115))/5 ,x=(10+sqrt(115))/5