What are the solutions to the equation factor 3x^2=-10x+8 ?

The solutions to the equation factor 3x^2=-10x+8 are x= 2/3 ,x=-4

Find the zeros of factor 3x^2=-10x+8

The zeros of factor 3x^2=-10x+8 are x= 2/3 ,x=-4

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3 x^{2} = - 10 x + 8

x = \frac{2}{3}, x = - 4

Decimal Notation

x = 0.66666 \dots, x = - 4

Solution steps

3 x^{2} = - 10 x + 8

Move

8

to the left side

3 x^{2} - 8 = - 10 x

Move

10 x

to the left side

3 x^{2} - 8 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 10 x - 8 = 0

Factor

3 x^{2} + 10 x - 8 : (3 x - 2) (x + 4)

(3 x - 2) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or x + 4 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 4

2 x^{2} + 3 x = 5

3 x^{2} + 2 x - 11 = 0

2 (x + 1)^{2} = x^{2} + 7 x - 2

(x + 1) (x + 2) = 3

x^{2} + 32 = 9 x

What are the solutions to the equation factor 3x^2=-10x+8 ?
The solutions to the equation factor 3x^2=-10x+8 are x= 2/3 ,x=-4
Find the zeros of factor 3x^2=-10x+8
The zeros of factor 3x^2=-10x+8 are x= 2/3 ,x=-4