What are the solutions to the equation 2a^2+2a-60=0 ?

The solutions to the equation 2a^2+2a-60=0 are a=5,a=-6

Find the zeros of 2a^2+2a-60=0

The zeros of 2a^2+2a-60=0 are a=5,a=-6

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2 a^{2} + 2 a - 60 = 0

a = 5, a = - 6

Solution steps

2 a^{2} + 2 a - 60 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 60) = 22

a_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 2 + 22}{2 \cdot 2}, a_{2} = \frac{- 2 - 22}{2 \cdot 2}

a = \frac{- 2 + 22}{2 \cdot 2} : 5

a = \frac{- 2 - 22}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

a = 5, a = - 6

(3 X - 1)^{2} + X (X - 3) = - 1

x^{2} - 10 x = x + 12

x^{2} - 2 x = 3

4 z^{2} - 4 z + 9 = 0

x^{2} - \frac{5}{2} x = 0

What are the solutions to the equation 2a^2+2a-60=0 ?
The solutions to the equation 2a^2+2a-60=0 are a=5,a=-6
Find the zeros of 2a^2+2a-60=0
The zeros of 2a^2+2a-60=0 are a=5,a=-6