What are the solutions to the equation y^2-15y-16=0 ?

The solutions to the equation y^2-15y-16=0 are y=16,y=-1

Find the zeros of y^2-15y-16=0

The zeros of y^2-15y-16=0 are y=16,y=-1

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y^{2} - 15 y - 16 = 0

y = 16, y = - 1

Solution steps

y^{2} - 15 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot (- 16) = 17

y_{1, 2} = \frac{- ( - 15 ) \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 17}{2 \cdot 1}, y_{2} = \frac{- ( - 15 ) - 17}{2 \cdot 1}

y = \frac{- ( - 15 ) + 17}{2 \cdot 1} : 16

y = \frac{- ( - 15 ) - 17}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

y = 16, y = - 1

6 x^{2} - x - 5 = 0

(y - 2)^{2} = 16

(z - 2)^{2} - 30 = 6

3 p^{2} - p + 5 = 0

x^{2} + 1 = 9

What are the solutions to the equation y^2-15y-16=0 ?
The solutions to the equation y^2-15y-16=0 are y=16,y=-1
Find the zeros of y^2-15y-16=0
The zeros of y^2-15y-16=0 are y=16,y=-1