What are the solutions to the equation 3x^2=16-2x ?

The solutions to the equation 3x^2=16-2x are x=2,x=-8/3

Find the zeros of 3x^2=16-2x

The zeros of 3x^2=16-2x are x=2,x=-8/3

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3 x^{2} = 16 - 2 x

x = 2, x = - \frac{8}{3}

Decimal Notation

x = 2, x = - 2.66666 \dots

Solution steps

3 x^{2} = 16 - 2 x

Move

2 x

to the left side

3 x^{2} + 2 x = 16

Move

16

to the left side

3 x^{2} + 2 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 16) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 3}, x_{2} = \frac{- 2 - 14}{2 \cdot 3}

x = \frac{- 2 + 14}{2 \cdot 3} : 2

x = \frac{- 2 - 14}{2 \cdot 3} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{8}{3}

0 = - x^{2} + 3

n^{2} + \frac{n}{3} = - 180

2 x^{2} - 6 x + 2

6 x^{2} - x - 2 = 0

7 y^{2} + 23 y - 20 = 0

What are the solutions to the equation 3x^2=16-2x ?
The solutions to the equation 3x^2=16-2x are x=2,x=-8/3
Find the zeros of 3x^2=16-2x
The zeros of 3x^2=16-2x are x=2,x=-8/3